Module 01 · Heat and Energy8 min read

Sensible Heat: Formula, Units and a Worked Boiler Example

Sensible heat is the heat that changes a substance’s temperature without changing its state. It is what a thermometer measures, what a feed tank gains from returning condensate, and what leaves a boiler through the stack.

ByShikhar Singh·Steam Consultant & IT Consultant·Published

You'll learn

  • Define sensible heat and tell it apart from latent heat
  • Use Q=mcpΔT in both kJ and kcal
  • Know why the specific heat of water is not exactly 4.18 at boiler temperatures
  • Work out what warmer feedwater is worth in fuel
BeginnerThe idea in plain words, and where you meet it. No maths.

What sensible heat is

Put heat into water at 30 °C and its temperature rises. Keep going and it reaches its boiling point, and from there the temperature stops rising even though heat keeps going in: the heat is now turning water into steam. The first kind of heat, the kind that shows up as a change in temperature, is called sensible heat, because you can sense it with a thermometer. The second kind is latent heat, and it has a lesson of its own.

How much heat it takes depends on three things: how much of the substance there is, how far you want to raise its temperature, and what the substance is. Water takes a lot of heat to warm up; steel takes about a tenth as much for the same mass; air about a quarter. That property, how much heat one kilogram needs per degree, is called its specific heat.

Where you meet sensible heat in a boiler house

  • Feedwater heating: the feed tank, the deaerator and the economizer all warm the water before it reaches the boiler, so the boiler has less to do.
  • Stack loss: flue gas leaves the chimney hotter than the air that came in. The heat it carries away is sensible heat, and it is the largest single loss in most boilers.
  • Thermic fluid heaters and hot water generators work on sensible heat alone. The fluid never boils; it gets hotter in the heater and cooler in the process.
  • Start-up: tonnes of steel and water have to be brought up to temperature before a boiler makes any steam, which is why a cold start burns fuel for nothing.
Heating curve for 1 kg of water at 10 kg/cm²(g): 651 kJ of sensible heat takes it from 30 °C to 183 °C, then 2,002 kJ of latent heat boils it at constant temperature.
Turning 1 kg of 30 °C water into steam at 10 kg/cm²(g). The sloping line is sensible heat; the flat line is latent heat. Chart: GyanTosh Fabricators Pvt. Ltd., reusable with credit under CC BY 4.0

The chart puts sensible heat in proportion. Of the 2,653 kJ it takes to make a kilogram of steam from cold water, only 651 kJ goes into raising the water to boiling point. The rest, about 75%, is latent heat.

IntermediateThe formula, its units, and a worked example on real plant numbers.

The formula

Sensible heat
Q=mcpΔT
Symbols in the formula
SymbolMeaningUnit
QHeat added or removedkJ (or kcal)
mMass of the substancekg
cpSpecific heat at constant pressurekJ/(kg·K)
ΔTTemperature change, final minus initialK, or °C

For a flow rather than a batch, replace the mass with a mass flow rate and the result is a heat rate: kg/h in, kJ/h out. Divide kJ/h by 3,600 for kW.

A temperature difference of 1 K is the same size as 1 °C, so ΔT can be worked in either. That is not true of temperatures themselves: anything that uses an absolute temperature, such as radiation or gas laws, needs kelvin.

Worked example: what warmer feedwater is worth

Worked example
Raising feedwater from 30 °C to 80 °C
Given
  • A 5 TPH boiler at 10 kg/cm²(g), running at full load: 5,000 kg/h of feedwater.
  • Feedwater today is cold make-up at 30 °C. Returning condensate to the feed tank would bring it to 80 °C.
  1. Heat the feedwater now gains in the tank instead of in the boiler, with cp = 4.18:
    Q=5,000×4.18×(80−30)=10,45,000 kJ/h
  2. Check against the steam table: water at 30 °C holds 126.7 kJ/kg and at 80 °C holds 335.8 kJ/kg, so the exact figure is 10,45,221 kJ/h. At these temperatures cpΔT is within a fraction of a percent.
  3. In other units: 290 kW, or 2.5 lakh kcal/h.
  4. As a share of the boiler’s work: turning 30 °C water into saturated steam at 10 kg/cm²(g) takes 2,653.3 kJ/kg. The tank now supplies 209.0 kJ/kg of that.
    209.02,653.3=7.9%
Answer: About 7.9% less fuel for the same steam, before counting the treated water the returned condensate also saves.
ExpertThe fine print: where the simple model breaks, and what it costs.

Specific heat of water at boiler temperatures

The textbook value for water is 4.18 kJ/(kg·K), and near room temperature it is right. It is not constant, though. Computed from the IAPWS-IF97 formulation for water held at 10 kg/cm²(g), as it is inside a running boiler:

Specific heat of liquid water at 10 kg/cm²(g)
Water temperaturecp, kJ/(kg·K)cp, kcal/(kg·°C)
20 °C4.180.999
50 °C4.180.998
80 °C4.191.002
100 °C4.211.007
120 °C4.241.014
150 °C4.311.029
180 °C4.411.052

Computed from IAPWS-IF97, region 1. Saturation at this pressure is 183.3 °C, so 180 °C is still liquid.

Between 20 and 100 °C the value barely moves. Above that it climbs, reaching 4.41 at 180 °C, about 5% more than 4.18. For a rough feedwater sum that error does not matter. For heating water to near its saturation temperature, or for an energy audit, use enthalpy from a steam table instead of cpΔT; the table already accounts for the change.

Other materials have much lower specific heats: plain carbon steel about 0.43 kJ/(kg·K) and air about 1.0, both near room temperature. Both also rise with temperature, and flue gas is not air: the water vapor in it has roughly twice the specific heat of air, so a wet fuel’s flue gas carries more heat per degree. That matters when a stack-loss calculation is the basis of an efficiency guarantee.

Why every 6 °C of feedwater is worth about 1% of fuel

The rule of thumb you will hear on site falls straight out of the energy balance. The fuel a boiler burns is proportional to the heat it adds to each kilogram of water, from feedwater enthalpy up to steam enthalpy, so the fraction saved by warmer feedwater is:

Fuel saved by warmer feedwater
saving=hfw,2−hfw,1hg−hfw,1
Symbols in the formula
SymbolMeaningUnit
hfw,1Enthalpy of feedwater before the improvementkJ/kg
hfw,2Enthalpy of feedwater after itkJ/kg
hgEnthalpy of the steam producedkJ/kg

From 30 to 36 °C at 10 kg/cm²(g) that gives 0.94%. The rule holds because the denominator, the total heat to make steam, is about 2,653 kJ/kg, while each 6 °C step adds only about 25. It assumes boiler efficiency stays the same. That is close to true when the feedwater is warmed by something outside the boiler, such as returned condensate. On a boiler with an economizer it is not: warmer water entering the economizer cools the flue gas less, the stack runs hotter, and part of the saving is lost.

Key takeaways

  • Sensible heat changes temperature, not state: Q=mcpΔT.
  • For water, cp is close to 4.18 kJ/(kg·K) up to 100 °C and rises to about 4.4 at 180 °C. Near saturation, use steam table enthalpies.
  • 1 kcal = 4.1868 kJ. Never mix the two inside one calculation.
  • Every 6 °C of feedwater temperature is worth roughly 1% of boiler fuel.

Check your understanding

Questions run from beginner to expert. Try each before opening the answer.

  1. Beginner

    Q1. Which of these is mainly a sensible heat process?

    1. A.Steam condensing in a jacketed vessel
    2. B.Thermic fluid being heated from 240 °C to 280 °C
    3. C.Water boiling in a boiler drum
    4. D.Flash steam forming at a trap outlet
    Show answer

    B. Thermic fluid stays liquid; only its temperature changes. The other three are all changes of state.

  2. Beginner

    Q2. Why is it called "sensible" heat?

    1. A.Because it is the sensible way to heat water
    2. B.Because a thermometer can sense it as a temperature change
    3. C.Because it can only be felt by touch
    4. D.Because it is measured in kcal
    Show answer

    B. Sensible heat shows up as a change in temperature, which a thermometer senses. Latent heat does not.

  3. Intermediate

    Q3. How much heat does it take to warm 2,000 kg of water from 40 °C to 70 °C, with cp = 4.18 kJ/(kg·K)?

    1. A.250,800 kJ
    2. B.25,080 kJ
    3. C.585,200 kJ
    4. D.8,360 kJ
    Show answer

    A. 2,000 × 4.18 × 30 = 250,800 kJ.

  4. Intermediate

    Q4. Why can a temperature difference be worked in °C even when cp is quoted per kelvin?

    1. A.Because 0 °C equals 0 K
    2. B.Because one kelvin and one degree Celsius are the same size
    3. C.Because water is incompressible
    4. D.It cannot; it must always be converted to kelvin
    Show answer

    B. The scales are offset by 273.15 but their steps are equal, so a difference is the same number in both.

  5. Expert

    Q5. Heating water from 120 °C to 180 °C, which is more accurate?

    1. A.cpΔT with cp = 4.18
    2. B.The difference in steam table enthalpies
    3. C.Both give the same answer
    4. D.cpΔT with cp = 1.0
    Show answer

    B. cp rises to about 4.41 at 180 °C, so a constant 4.18 understates the heat by a few percent. Enthalpy from the table already includes the change.

Frequently asked

What is sensible heat?
Sensible heat is heat that changes the temperature of a substance without changing its state. Heating water from 30 °C to 80 °C is sensible heat; boiling it into steam at constant temperature is latent heat.
What is the formula for sensible heat?
Q = m × cp × ΔT: heat equals mass, times specific heat at constant pressure, times the temperature change. For water near room temperature cp is about 4.18 kJ/(kg·K), or 1 kcal/(kg·°C).
What is the specific heat of water in kcal?
About 1 kcal/(kg·°C) near room temperature, which is how the kilocalorie was originally defined. In SI units it is about 4.18 kJ/(kg·K), rising to about 4.4 at 180 °C.
What is the difference between sensible heat and latent heat?
Sensible heat changes temperature and can be measured with a thermometer. Latent heat changes state, liquid to vapor or back, at constant temperature. Making steam from cold water needs both: sensible heat to reach the boiling point, then latent heat to boil it.

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About the author

Shikhar SinghSteam Consultant & IT Consultant

Shikhar Singh is a Steam Consultant and IT Consultant at GyanTosh Fabricators Pvt. Ltd., where he works on steam system sizing, condensate recovery and the engineering content published on this site.

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