Module 05 · Boiler Water4 min read

TDS Control and Blowdown: How Much Water to Throw Away

A boiler concentrates the dissolved solids in its feedwater. Left alone, the concentration rises until the water foams and carries over into the steam. Blowdown removes a little concentrated water continuously or in bursts, replacing it with fresher feed. Getting the amount right is a balance between water quality and wasted heat.

ByShikhar Singh·Steam Consultant & IT Consultant·Published

You'll learn

  • Explain why TDS rises and why it must be limited
  • Calculate blowdown from feedwater and boiler TDS
  • Work out the heat lost in blowdown
  • Compare continuous and intermittent blowdown, and heat recovery

Before this: Raw water quality, Softeners and RO

BeginnerThe idea in plain words, and where you meet it. No maths.

Why water has to be thrown away

Steam leaves the boiler almost pure; the dissolved solids that came in with the feedwater stay. Every hour, the boiler water gets a little more concentrated. Above a certain level it starts to foam, the foam is carried out with the steam, and dissolved solids and water end up in the steam mains and on the process. Sludge also settles at the bottom.

Blowdown is the deliberate removal of some boiler water to keep the concentration below its limit. It is necessary, and it is also a loss: the water removed is at boiler temperature and has already been treated.

IntermediateThe formula, its units, and a worked example on real plant numbers.

How much blowdown

Blowdown as a percentage of evaporation
B=TDSfeedTDSmax⁡−TDSfeed×100
Symbols in the formula
SymbolMeaningUnit
TDSfeedDissolved solids in the feedwaterppm
TDSmax⁡Maximum allowed in the boiler waterppm
Worked example
Blowdown for a 2 TPH boiler
Given
  • Feed TDS 300 ppm; boiler water held at 3,000 ppm; 2,000 kg/h of steam at 10 kg/cm²(g); feedwater 80 °C.
  1. Blowdown percentage:
    3003,000−300×100=11.1%
  2. Blowdown flow: 2,000 × 0.111 = 222 kg/h.
  3. Each kilogram leaves at 778.0 kJ/kg, having come in at 335.8 kJ/kg. Heat lost: 222 × 442.2 = 98,264 kJ/h (27 kW).
Answer: About 2.0% of the boiler’s heat output goes down the drain — plus the treated water and chemicals in 222 kg/h.
ExpertThe fine print: where the simple model breaks, and what it costs.

Continuous, intermittent and recovered

  • Intermittent (bottom) blowdown: short, fast blows from the lowest point to remove sludge. Necessary, but a poor way to control TDS: concentration swings up and down.
  • Continuous (surface) blowdown: a small, steady flow taken from just below the water surface, where concentration is highest. Holds TDS steady, close to its limit, which minimizes the water thrown away.
  • Automatic TDS control: a conductivity probe measures boiler water TDS and opens a blowdown valve only when needed. It removes the guesswork that usually leads operators to blow down too much.

Because continuous blowdown is steady, its heat can be recovered. Passed into a flash vessel at about 0.2 kg/cm²(g), roughly 15% of it flashes to low-pressure steam that can feed the deaerator; the remaining hot water can preheat make-up through a heat exchanger before it goes to drain. Together they recover most of the blowdown heat.

Key takeaways

  • Blowdown keeps boiler water TDS below the limit at which it foams and carries over.
  • Blowdown % = feed TDS ÷ (max TDS − feed TDS) × 100.
  • At 300 ppm feed and 3,000 ppm limit: 11.1% blowdown, about 2.0% of boiler heat.
  • Continuous, automatic blowdown with flash and heat recovery minimizes the loss.

Check your understanding

Questions run from beginner to expert. Try each before opening the answer.

  1. Beginner

    Q1. Why does boiler water TDS keep rising?

    1. A.Steam carries salts in
    2. B.Steam leaves nearly pure, so the solids stay behind
    3. C.Chemicals add TDS
    4. D.Scale dissolves
    Show answer

    B. Solids concentrate as water evaporates.

  2. Intermediate

    Q2. Feed TDS 200 ppm, limit 2,200 ppm. Blowdown %?

    1. A.5%
    2. B.10%
    3. C.11%
    4. D.20%
    Show answer

    B. 200 / (2,200 − 200) × 100 = 10%.

  3. Intermediate

    Q3. Which blowdown controls TDS best?

    1. A.Bottom blowdown once a shift
    2. B.Continuous surface blowdown, ideally automatic
    3. C.No blowdown
    4. D.Opening the drain fully
    Show answer

    B. A steady flow holds TDS close to its limit.

  4. Expert

    Q4. How can blowdown heat be recovered?

    1. A.It cannot
    2. B.Flash vessel for low-pressure steam, then a heat exchanger to preheat make-up
    3. C.By cooling it with air
    4. D.By returning it to the boiler
    Show answer

    B. Flash steam and the residual hot water both carry recoverable heat.

Frequently asked

How do you calculate boiler blowdown?
Blowdown as a percentage of steam = feedwater TDS ÷ (maximum boiler water TDS − feedwater TDS) × 100. With 300 ppm feed and a 3,000 ppm limit it is 11.1%.
What is the difference between continuous and intermittent blowdown?
Continuous blowdown takes a steady small flow from near the water surface to control dissolved solids; intermittent bottom blowdown removes sludge in short bursts.

Training a boiler team?

These lessons follow the order we train operators in. We also run on-site operator and maintenance training, built around your own plant.

Boiler operator training →

Sources

About the author

Shikhar SinghSteam Consultant & IT Consultant

Shikhar Singh is a Steam Consultant and IT Consultant at GyanTosh Fabricators Pvt. Ltd., where he works on steam system sizing, condensate recovery and the engineering content published on this site.

Full profile and background →